Penjelasan dengan langkah-langkah:
[tex]no = \sqrt{5 {}^{2} + 4 {}^{2} } \\ = \sqrt{25 + 16} \\ = \sqrt{41} [/tex]
jadi, panjang NO = √41 cm
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Penjelasan dengan langkah-langkah:
[tex]no = \sqrt{5 {}^{2} + 4 {}^{2} } \\ = \sqrt{25 + 16} \\ = \sqrt{41} [/tex]
jadi, panjang NO = √41 cm