Question

Tentukan p-q. jika p = 6-3akar 27, q=4+akar 12
tolong ya

Answer 1

Verified answer

Materi : Akar dan pangkat

Pembahasan :
P - Q
= [6 - 3√27] - [4 + √12]
= [6 - 3√(9.3)] - [4 + √(4.3)]
= 6 - 9√3 - 4 - 2√3
= 2 - 11√3

Answer 2

Verified answer

(6 - 3√27) - (4 + √12)
=(6 - 3 x √9 x √3) - (4 + √4 x √3)
=(6 - 3 x 3√3) - (4 + 2√3)
=6 - 9√3 - 4 - 2√3
=2 - 11√3

Jadikan jawaban terbaik lg ya dek