August 2018 1 12 Report
Tentukan nilai x
1. 6^{x+2} = (36) ^{x+2}
2. 5^{x+2} = \sqrt[4]{25} ^{x+3}
3. \sqrt{5} ^{x-1} = 1
4.( \sqrt{10} ^{x-2} = 0,1
5. \sqrt{2} ^{x+3} = ( \frac{1}{4} ) ^{x+4}

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