Question

"Tentukan nilai X dari Log (x-2)+Log(x-1)=log6"

Answer 1

Log(x-2)+log(x-1)=log6
log(x-2)(x-1) = log 6
(x-2)(x-1) = 6
x^2 -3x +2 = 6
x^2 - 3x -4 = 0
(x-4)(x+1)=0
x-4 = 0
x = 4

atao
x+1=0
x= -1

Answer 2

Log 6 = log (2 × 3)
log 6 = log 2 + log 3

log (x - 2) + log (x - 1) = log 2 + log 3
x - 2 = 2
x - 1 = 3

berarti x = 4

semoga benar yaa... ;-)