Question

tentukan nilai X dan Y​

Answer 1

Materi : Teorama Phytagoras

Soal Nomor 1

x² = 10² - 6²

x² = 100 - 36

x² = 64

x = 8

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y² = 17² - x²

y² = 289 - 64

y² = 225

y = 15

Soal Nomor 2

x² = 12² + 5²

x² = 144 + 25

x² = 169

x = 13

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( y + 5 )² = 20² - 12²

( y + 5 )² = 400 - 144

( y + 5 )² = 256

y + 5 = 16

y = 11

Soal Nomor 3

( x + 14 )² = 25² - 7²

( x + 14 )² = 625 - 49

( x + 14 )² = 576

x + 14 = 24

x = 10

---

y² = 26² - x²

y² = 676 - 100

y² = 576

y = 24

Semoga bisa membantu

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Answer 2

1) X = √10² - 6²

= √(10(10) - (6(6)

= √100 - 36

= √64

= √(8(8)

= √8²

= 8

===============

Y = √17² - 8²

= √(17(17) - (8(8)

= √289 - 64

= √225

= √(15(15)

= √15²

= 15

2) X = √12² + 5²

= √(12(12) + (5(5)

= √144 + 25

= √169

= √(13(13)

= √13²

= 13

===============

Y + 5 = √20² - 12²

Y + 5 = √(20(20) - (12(12)

Y + 5 = √400 - 144

Y + 5 = √256

Y + 5 = √(16(16)

Y + 5 = √16²

Y + 5 = 16

Y = 16 - 5

Y = 11

3) X + 14 = √25² - 7²

X + 14 = √(25(25) - (7(7)

X + 14 = √625 - 49

X + 14 = √576

X + 14 = √(24(24)

X + 14 = √24²

X + 14 = 24

X = 24 - 10

X = 20

======================

Y = √26² - 10²

= √(26(26) - (10(10)

= √676 - 100

= √576

= √(24(24)

= √24²

= 24