[tex] \frac{{4}^{3x + 1}}{ {2}^{2x - 5} } \\ \\ \frac{ {2}^{6x + 2} }{ {2}^{2x - 5} } \\ \\ 4x + 7\\ 4x = - 7 \\ \boxed{x = - \frac{7}{4}} [/tex]
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
[tex] \frac{{4}^{3x + 1}}{ {2}^{2x - 5} } \\ \\ \frac{ {2}^{6x + 2} }{ {2}^{2x - 5} } \\ \\ 4x + 7\\ 4x = - 7 \\ \boxed{x = - \frac{7}{4}} [/tex]