Penjelasan dengan langkah-langkah:
[tex]a. \ sin (150^{o}) =sin (90 +60)=cos (60^{o})=\frac{1}{2}\\b.\ cos(-210^{o} )=cos (210^{o})=cos(180+30)=-sin(30^{o})= -\frac{1}{2}\\c.\ tan (330^{o})=tan (360-30)=-tan(30^{o})=-\frac{1}{3}\sqrt{3}\\d.\ sec(60^{o})= \frac{1}{cos(60^{o}) }=\frac{1}{0,5}=2[/tex]
Semoga membantu [^_^]
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Penjelasan dengan langkah-langkah:
[tex]a. \ sin (150^{o}) =sin (90 +60)=cos (60^{o})=\frac{1}{2}\\b.\ cos(-210^{o} )=cos (210^{o})=cos(180+30)=-sin(30^{o})= -\frac{1}{2}\\c.\ tan (330^{o})=tan (360-30)=-tan(30^{o})=-\frac{1}{3}\sqrt{3}\\d.\ sec(60^{o})= \frac{1}{cos(60^{o}) }=\frac{1}{0,5}=2[/tex]
Semoga membantu [^_^]