Question

Tentukan nilai r pada persamaan bentuk aljabar (2x + 3y)(px + qy) = rx^2 + 23xy + 12y^2

Answer 1

(2x+3y)(px+qy) = rx^2+2xy+12y^2
(2x+3y)(px+4y) = rx^2+2xy+12y^2
2px^2+8xy+3pxy+12y^2 = rx^2+2xy+12y^2
2*-2x^2+8xy+3*-2xy+12y^2 = rx^2+2xy+12y^2
-4x^2+8xy-6xy+12y^2 = -4x^2+2xy+12y^2

p = -2
q = 4
r = -4