Question

Tentukan nilai maksimum dan minimum pada interval f(x) = x4 - 4x2 pada interval [ -2,4 ]

Answer 1

Y=x^4-4x²
f(-2)=16-4.4=0
f(4)=16.16-4.16 = 12.16
y ' = 4x³-8x = 0
y' = 4x(x²-2) = 0
x=0, x = √2, x = -√2
f(0) = 0
f(√2) = f(-√2) = 4-4.2=-4
nilai minimum = - 4, nilai maks = 192