a.Nilai maksimum terjadi ketika sin nya sin 90 , supaya sin nya sin 90 , maka 2x = 150 <= x = 75
f(75) = 2.sin(2.75 - 60) + 2
= 2.sin(150-60)+2
= 2.sin(90) + 2
f(75) = 2.1 + 2
f(75) = 4
b. Nilai Minimum terjadi ketika sin nya sin 270 , supaya sin nya 270 derajat , maka 2x = 330, x = 165
f(165) = 2.sin(2.165-60) + 2
f(165) = 2.sin(270)+2
f(165) = -2+2
f(165) = 0
c. Nilai maks = 4 , nilai min = 0
Tri6ono|\/|3tri
F(x) = 2 sin (2x - 60°) + 2
•
Nilai maksimum sin (2x - 60°) = 1
Maka
Nilai maksimum f(x) = 2.1 + 2 = 4 ✔
••
Nilai minimum sin (2x - 60°) = -1
Nilai minimum f(x) = 2(-1) + 2 = 0 ✔
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Verified answer
a.Nilai maksimum terjadi ketika sin nya sin 90 , supaya sin nya sin 90 , maka 2x = 150 <= x = 75
f(75) = 2.sin(2.75 - 60) + 2
= 2.sin(150-60)+2
= 2.sin(90) + 2
f(75) = 2.1 + 2
f(75) = 4
b. Nilai Minimum terjadi ketika sin nya sin 270 , supaya sin nya 270 derajat , maka 2x = 330, x = 165
f(165) = 2.sin(2.165-60) + 2
f(165) = 2.sin(270)+2
f(165) = -2+2
f(165) = 0
c. Nilai maks = 4 , nilai min = 0
Tri6ono|\/|3tri
F(x) = 2 sin (2x - 60°) + 2
•
Nilai maksimum sin (2x - 60°) = 1
Maka
Nilai maksimum f(x) = 2.1 + 2 = 4 ✔
••
Nilai minimum sin (2x - 60°) = -1
Maka
Nilai minimum f(x) = 2(-1) + 2 = 0 ✔