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y = (2 - k)x - 8
m = 2 - k
(4 + k)x + 3y = 12
3y = - (4 + k)x + 12
y = (-1/3)(4 + k)x + 4
m = - (4 + k)/3
agar tegak lurus maka perkalian gradiennya = - 1
- (2 - k)(4 + k)/3 = - 1
8 + 2k - 4k - k² = 1
k² + 2k + 7 = 0
cari k nya