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3y - 2x + 4 = 0 --->m1 = 2/3
2k x + 13 + y = 0 ---> m2 = - 2k
m1 = m2
2/3 = -2 k
-6 k = 2
k = - 1/3
3y - 2x + 4 = 0
3y = 2x - 4
y = 2/3 x - 4/3
m1 = 2/3
2k x + 13 + y = 0
t = -2k x - 13
m2 = -2k
dua buah garis dikatakan sejajar apabila gradiennya sama
m1 = m2
2/3 = -2 k
-2k = 2/3 kalika 3
-6 k = 2
k = -2/6
k = - 1/3