Question

Tentukan nilai H+ jika;
a. [OH-] = 0,02 M >>> [H+] =.....
b. [OH-]= 5×10^4 M >>> [H+] =....

Answer 1

A. [OH-] = 0,02 ➡2×10^-2
⤵
pOH= -log [OH-]
= -log [2×10^-2]
=2-log 2
⤵
pH= 14 - (2-log 2)
=12+ log2
⤵
[H+]= 2×10^12

b.[OH-]=5×10^4
⤵
pOH=-log[5×10^4]
=4+log 5
⤵
pH=14 - (4+log5)
=10-log 5
⤵
[H+]= 5×10^-10