lim x→0 (3 cos 4x - 3)/(6x sin 3x)
= lim x→0 3(cos 4x - 1) / 6x sin 3x
= lim x→0 - 2sin² 2x / 2x sin 3x
= lim x→0 - (sin 2x)/x . (sin 2x / sin 3x)
= - 2/1 . 2/3
= - 4/3
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
lim x→0 (3 cos 4x - 3)/(6x sin 3x)
= lim x→0 3(cos 4x - 1) / 6x sin 3x
= lim x→0 - 2sin² 2x / 2x sin 3x
= lim x→0 - (sin 2x)/x . (sin 2x / sin 3x)
= - 2/1 . 2/3
= - 4/3