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12+3y-z=12
x-2y+3z=6
1.)
x+y+z =8
x-2y+3z=6 (dikurangi) = 3y-2z =2
2.)
3y-2z =2
3y-z=0 (dikurangi) = z=2
3.)
3y-2=0
3y = 2
y = 2/3
4.)
x+2/3+2 =8
x = 8-2-2/3
x= 6 -2/3
3x = 18 - 2
3x = 16
x= 16/3
jadi x = 16/3 , y = 2/3 , z = 2