بِسْــــــمِ اللّٰهِ الرَّحْمٰنِ الرَّحِيْمَ
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Jawaban:
Penjelasan dengan langkah-langkah:
Nomor 1
[tex]\begin{aligned}\displaystyle&\lim_{x \to 3} 4x + 2\\&=4(3) + 2 \\ &=12 + 2 \\&=14 \end{aligned}[/tex]
Nomor 2
[tex]\begin{aligned}\displaystyle&\lim_{x \to - 1} (3x + 2) + ( {x}^{2} + 1)\\&=(3( - 1) + 2) + ( {( - 1)}^{2} + 1) \\ &=( - 3 + 2) + (1 + 1) \\&= - 1 + 2 \\ &=1\end{aligned}[/tex]
Nomor 3
[tex]\begin{aligned}\displaystyle&\lim_{x \to 2} \: (2x + 3) ( 5x - 4)\\&=(2(2) + 3)(5(2) - 4)\\ &=(4 + 3)(10 - 4)\\&= (7)(6)\\ &=42\end{aligned}[/tex]
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بِسْــــــمِ اللّٰهِ الرَّحْمٰنِ الرَّحِيْمَ
..
Jawaban:
Penjelasan dengan langkah-langkah:
Nomor 1
[tex]\begin{aligned}\displaystyle&\lim_{x \to 3} 4x + 2\\&=4(3) + 2 \\ &=12 + 2 \\&=14 \end{aligned}[/tex]
Nomor 2
[tex]\begin{aligned}\displaystyle&\lim_{x \to - 1} (3x + 2) + ( {x}^{2} + 1)\\&=(3( - 1) + 2) + ( {( - 1)}^{2} + 1) \\ &=( - 3 + 2) + (1 + 1) \\&= - 1 + 2 \\ &=1\end{aligned}[/tex]
Nomor 3
[tex]\begin{aligned}\displaystyle&\lim_{x \to 2} \: (2x + 3) ( 5x - 4)\\&=(2(2) + 3)(5(2) - 4)\\ &=(4 + 3)(10 - 4)\\&= (7)(6)\\ &=42\end{aligned}[/tex]