Jawab:
Limit dengan subsitusi
Penjelasan dengan langkah-langkah:
a) lim(x-> -1) (x² -8x + a ) = 18
substitusikan x= -1 --> (-1)² -8 (-1) + a = 18
1 + 8+ a =18
a= 9
b) lim(x->1 ) (3x - a) / (4x² - 2√x) = 4
sub x = 1 --> (3.1 - a) / (4.1² - 2√1) = 4
(3 - a) /(4-2) = 4
3 - a = 2(4)
3 - a = 8
a = - 5
c) lim(x-> a) (2x - 6) /(8 - x ) = 4/3
substitusikan x = a --> (2.a - 6 ) / (8 - a) = 4/3
(2a - 6)/(8 - x) = 4/3 ...kali silang
3(2a - 6 ) = 4 (8 - a)
6a - 18 = 32 - 4a
6a + 4a = 32 + 18
10 a = 50
a = 5
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Verified answer
Jawab:
Limit dengan subsitusi
Penjelasan dengan langkah-langkah:
a) lim(x-> -1) (x² -8x + a ) = 18
substitusikan x= -1 --> (-1)² -8 (-1) + a = 18
1 + 8+ a =18
a= 9
b) lim(x->1 ) (3x - a) / (4x² - 2√x) = 4
sub x = 1 --> (3.1 - a) / (4.1² - 2√1) = 4
(3 - a) /(4-2) = 4
3 - a = 2(4)
3 - a = 8
a = - 5
c) lim(x-> a) (2x - 6) /(8 - x ) = 4/3
substitusikan x = a --> (2.a - 6 ) / (8 - a) = 4/3
(2a - 6)/(8 - x) = 4/3 ...kali silang
3(2a - 6 ) = 4 (8 - a)
6a - 18 = 32 - 4a
6a + 4a = 32 + 18
10 a = 50
a = 5