" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Verified answer
Bab TrigonometriMatematika SMA Kelas X
tan 255° = tan (210° + 45°)
= (tan 210° + tan 45°) / (1 - tan 210° . tan 45°)
= (1/3 . √3 + 1) / (1 - 1/3 . √3 . 1)
= (√3 + 3)/3 : ((3 - √3)/3)
= ((3 + √3)/3) x (3/(3 - √3))
= (3 + √3)/(3 - √3)
= (3 + √3) (3 + √3) / (3² - √3²)
= (9 + 6√3 + √3²) / (9 - 3)
= (9 + 6√3 + 3) / 6
= (12 + 6√3) / 6
= 2 + √3
Verified answer
Trigonometry.Use complementary angle and half angle formula!
tan (180° + θ) = tan θ
tan 1/2 A = ±√[(1 - cos A) / (1 + cos A)] = (1 - cos A) / sin A = sin A / (1 + cos A)
tan 255° = tan 75°
= sin 150° / (1 + cos 150°)
= 1/2 / (1 - 1/2 √3)
= 1/2 / (2 - √3) / 2
= 1 / (2 - √3) [(2 + √3) / (2 + √3)]
= 2 + √3