Materi : Bangun Ruang Sisi Lengkung
Lp = πr² + πdt + πrs
Lp = π( 5² + 10.30 + 5.5√17
Lp = 3,14( 25 + 300 + 25√17 )
Lp = 3,14( 325 + 25√17 )
Lp = ( 1.020,5 + 78,5√17 ) cm²
Semoga bisa membantu
[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]
Jawaban:
Luas permukaan
= πr² + πdt + πrs
= π( 5² + 10.30 + 5.5√17
= 3,14( 25 + 300 + 25√17 )
= ( 1.020,5 + 78,5√17 ) cm²
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Verified answer
Materi : Bangun Ruang Sisi Lengkung
Lp Tabung + Kerucut
Lp = πr² + πdt + πrs
Lp = π( 5² + 10.30 + 5.5√17
Lp = 3,14( 25 + 300 + 25√17 )
Lp = 3,14( 325 + 25√17 )
Lp = ( 1.020,5 + 78,5√17 ) cm²
Semoga bisa membantu
[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]
Jawaban:
Luas permukaan
= πr² + πdt + πrs
= π( 5² + 10.30 + 5.5√17
= 3,14( 25 + 300 + 25√17 )
= ( 1.020,5 + 78,5√17 ) cm²