Penjelasan dengan langkah-langkah:
PR = 12 cm → 90°
PQ = ? → 30°
Mencari PQ.
PQ/sin 30° = PR/sin 90°
PQ/(1/2) = 12/1
2PQ = 12
PQ = 12/2
PQ = 6 cm
Mencari QR/PS
= √(12² - 6²)
= √(144 - 36)
= √108
= √(36.3)
= 6√3 cm
Mencari Luas persegi panjang PQRS.
L = p x l ATAU L = PQ x QR
L = 6√3 x 6 cm
L = 36√3 cm² ✓
∆ PQR
PQ = X
PR = 2X
QR = X√3
12 CM = 2x
X = 6 cm
PQ = X = 6 CM
QR = x√3 = 6√3 cm
L = p X l
L = PQ X QR
L = 6 X 6√3
L = 36√3 cm²
kelas : 8 SMP
materi : Segitiga Istimewa
mapel : matematika
kode soal : 2
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Verified answer
Penjelasan dengan langkah-langkah:
PR = 12 cm → 90°
PQ = ? → 30°
Mencari PQ.
PQ/sin 30° = PR/sin 90°
PQ/(1/2) = 12/1
2PQ = 12
PQ = 12/2
PQ = 6 cm
Mencari QR/PS
= √(12² - 6²)
= √(144 - 36)
= √108
= √(36.3)
= 6√3 cm
Mencari Luas persegi panjang PQRS.
L = p x l ATAU L = PQ x QR
L = 6√3 x 6 cm
L = 36√3 cm² ✓
∆ PQR
PQ = X
PR = 2X
QR = X√3
PR = 2X
12 CM = 2x
X = 6 cm
PQ = X = 6 CM
QR = x√3 = 6√3 cm
L = p X l
L = PQ X QR
L = 6 X 6√3
L = 36√3 cm²
Detail jawaban
kelas : 8 SMP
materi : Segitiga Istimewa
mapel : matematika
kode soal : 2