5dregensleyer
T1 = √13² - 5² = √196 - 25 = √144 = 12 cm a = (26-20) : 2 = 6 : 2 = 3 cm t2 = √5² - 3² = √25 - 9 = √16 = 4 cm luas seluruh bngun luas = ( 2 x 1/2 x a x t) + ( (a+b) x t/2) = ( a x t ) + ( ( 20+26) x 4/2) = ( 5 x 12) + ( 46 x 2) = 60 + 84 = 144 cm²
= √196 - 25
= √144
= 12 cm
a = (26-20) : 2
= 6 : 2
= 3 cm
t2 = √5² - 3²
= √25 - 9
= √16
= 4 cm
luas seluruh bngun
luas = ( 2 x 1/2 x a x t) + ( (a+b) x t/2)
= ( a x t ) + ( ( 20+26) x 4/2)
= ( 5 x 12) + ( 46 x 2)
= 60 + 84
= 144 cm²