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b = 7
Sn = n/2 (2a + (n - 1)b)
2(285) = n (2(-3) + (n - 1)7)
570 = n (-6 + 7n - 7)
570 = n (-15 + 7n)
570 = -13n + 7n²
7n² - 13n - 570 = 0
(7n + 57)(n - 10)
n = -57/7 atau n = 10
ambil yang bilangan bulat, maka n = 10
Un = a + (n-1)b
U10 = a + (10 - 1)b
U10 = a + 9b
= -3 + 9(7)
= -3 + 63
= 60
l = 60
Sehingga, nilai I :