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Verified answer
LarutanKimia XI
H₂SO₄ → 2H⁺ + SO₄²⁻
0,02 M....0,04 M
Diperoleh konsentrasi H⁺ sebesar 4 x 10⁻² M
Karena [H⁺] x [OH⁻] = 10⁺¹⁴, maka
[4 x 10⁻²] x [OH⁻] = 10⁺¹⁴
[OH⁻] = 10⁺¹⁴ x ¹/₄ x 10²
Diperoleh konsentrasi OH⁻ sebesar 2,5 x 10⁻¹³ M