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U1 = a = 12, b = 3
Un =a + (n-1)b = 99
Un =12 + 3n - 3 = 99
9 + 3n = 99
3n = 30
n = 10
S10 = 10/2 (2a+ 9b)
S10 = 5(24 + 27)
S10 = 5(51)
S10 = 255
12, 15,18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63, 66, 69, 72, 75, 78, 81, 84, 87, 90, 93, 96, 99.
n = 30
99 + 12 = 111
96 + 15 = 111
maka, jumlah bilangan antara 10 dan 100 yang habis dibagi 3 sebesar
111 x 15 =1665