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3a-2b+c = 5 .... (i)
a-5b+3c = 2 .... (ii)
2a+b+c = 12 .... (iii)
eliminasi pers (i) dan (ii)
3a-2b+c = 5 (x3) --> 9a-6b+3c = 15
a-5b+3c = 2 (x1) --> a-5b+3c = 2 _
8a-b = 13 .... (iv)
eliminasi (i) dan (iii)
3a-2b+c = 5
2a+b+c = 12 _
a-3b = -7 (v)
eliminasi (iv) dan (v)
8a-b = 13 (x3) --> 24a-3b = 39
a-3b = -7 (x1) --> a-3b = -7 _
23a = 46
a = 2
sustitusi a=2 ke (v)
2-3b = -7
-3b = -7-2
b = -9/-3
b = 3
substitusi ke (i)
3a-2b+c = 5
3.2 - 2.3 + c = 5
c = 5
a = 2 --> 1/x = 2 --> x = 1/2
b = 3 --> 1/y = 3 --> y = 1/3
c = 5 --> 1/z = 5 --> z = 1/5