substitusi 1&2
x+y+z=2
2x-y+3z=-3
→2x+2y+2z=4
→2x-y+3z=-3
3y-z=7 ...(1)
substitusi 1&3
x+2y-2z=7
-y+3z=-5 ...(2)
substitusi persamaan 1&2
3y-z=7
-y+3z=-5
→9y-3z=21
→-y+3z=-5
8y=16
-2+3z=-5
3z=-3
x+2-1=2
x=2-1
maaf klo salah ya
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substitusi 1&2
x+y+z=2
2x-y+3z=-3
→2x+2y+2z=4
→2x-y+3z=-3
3y-z=7 ...(1)
substitusi 1&3
x+y+z=2
x+2y-2z=7
-y+3z=-5 ...(2)
substitusi persamaan 1&2
3y-z=7
-y+3z=-5
→9y-3z=21
→-y+3z=-5
8y=16
y=2
-y+3z=-5
-2+3z=-5
3z=-3
z=-1
x+y+z=2
x+2-1=2
x=2-1
x=1
hp{-1,1,2}
maaf klo salah ya