Question

Tentukan himpunan penyelesaian persaman berikut. 2log (x-3)+2log (x-2)=1

Answer 1

2log(x-3) + 2log(×-2) = 2log2
(×-3)(×-2) = 2 (2log bisa di hilangkan)
×2 - 5× + 6 = 2
×2 - 5× + 4 = 0
(×-4)(×-1) = 0
× = 4
× = 1

Hp = {4,1}

Answer 2

²log (x-3) + ²log (x-2) = 1
²log (x-3) (x-2) = 1
²log x² - 5x + 6 = 1
⇔x² - 5x + 6 = 2¹
x² - 5x + 6 - 2 = 0
x² - 5x + 4 = 0
(x - 1) (x - 4) = 0

⇒ x - 1 = 0
         x = 1
⇒ x - 4 = 0
         x = 4

HP = {1 , 4} 

maaf kalo salah, cuma asal jawab :)