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2) 5x + y - z = 5
6x - 2y = 4 .... pers 1
2) 5x + y - z = 5
3) 8x - 6y - z = 1
-3x + 7y = 4 ... pers 2
masukkan pers 1 dan pers 2
6x - 2y = 4 [ .1 ] 6x - 2y = 4
-3x + 7y = 4 [ .2 ] -6x + 14y = 8
12y = 12
y = 1
6x - 2y = 4
6x - 2(1) = 4
6x = 4 + 2
6x = 6
x = 1
kemudian x - 3y + z = -1
(1) - 3(1) + z = -1
1 - 3 + z = -1
z = -1 + 2
z = 1
pembuktian kembali
soal 1
x - 3y + z = -1
(1) - 3(1) + 1 = -1
1 - 3 + 1 = -1
-1 = -1
jadi nilai x = 1 , y = 1 , z = 1
persamaan 3 dan 4 di eliminasi
kemudia di substitusikan