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-4 < 4x < -2
-1 < x < -1/2
b. x^2 + 6x + 9 <= 4x^2
3x^2 - 6x - 9 >= 0
x^2 - 2x - 3 >= 0
(x+1)(x-3) >= 0
x<= -1 atau x >= 3
|4x + 3| < 1
-1 < 4x +3 < 1
-4 < 4x < -2
-1 < x < -
b.
|x + 3| < |2x|
(|x + 3|)² < (|2x|)²
x² + 6x + 9 < 4x²
-3x² + 6x + 9 < 0
x² - 2x - 3 > 0
(x - 3)(x + 1)
x = 3 atau x = -1
+ - +
------o-------o-------
-1 3
Jadi jawabannya
x < -1 atau x > 3