Question

tentukan hasil perkalian bentuk aljabar berikut dalam jumlah atau selisih (3×-6)(4×-4)​

Answer 1

a. (2x + 3) (3x -2)

= 2x . 3x + 2x . (-2) + 3 x 3x + 3 x (-2)

=6x^2 - 4x + 9x - 6

= 6x^2 + 5x - 6

b. (-4a + b) (4a + b)

=-4a x 4a + (-4a) x b + b x 4a + b x b

=-16a^2 - 4ab + 4ab + b^2

=-16a^2 + b^2

c. (2x - 1) (x^2 - 2x + 4)

=2x x x^2 + 2x x (-2x) + 2x x 4 + (-1) x x^2 + (-1) x (-2x) + (-1) x 4

=2x^3 - 4x^2 + 8x - x^2 + 2x -4

=2x^3 - 5x^2 +10x - 4

d. (x + 2) (x - 2)

= x x x + x x (-2) + 2 x x + 2 x (-2)

=x^2 -2x +2x - 4

=x^2 -4