Question

Tentukan hasil perkalian bentuk aljabar berikut dalam bentuk jumlah atau selisih a.(2x+3)(3x-2) b.(-4a+b)(4a+2b) c.(2x-1)(x2-2x+4) d.(x+2)(x-2) dengan caranya

Answer 1

A)(2x+3)(3x-2)
=6x²-4x+9x-6
=6x²+5x-6
b)(-4a+b)(4a+2b)
=-16a²-8ab+4ab+2b²
=-16a²-4ab+2b²
c)(2x-1)(x²-2x+4)
=2x³+4x²+8x-x²+2x-4
=2x³+4x²-x²+8x+2x-4
=2x³+3x²+10x-4
d)(x+2)(x-2)
=x²-2x+2x-4
=x²-x-4
Semiga membantu^_^

Answer 2

A. (2x + 3) (3x -2)
= 2x . 3x + 2x . (-2) + 3 x 3x + 3 x (-2)
=6x^2 - 4x + 9x - 6
= 6x^2 + 5x - 6

b. (-4a + b) (4a + b)
=-4a x 4a + (-4a) x b + b x 4a + b x b
=-16a^2 -  4ab + 4ab + b^2
=-16a^2 + b^2

c. (2x - 1) (x^2 - 2x + 4)
=2x x x^2 + 2x x (-2x) + 2x x 4 + (-1) x x^2 + (-1) x (-2x) + (-1) x 4
=2x^3 - 4x^2 + 8x - x^2 + 2x -4
=2x^3 - 5x^2 +10x - 4

d. (x + 2) (x - 2)
= x x x + x x (-2) + 2 x x + 2 x (-2)
=x^2 -2x +2x - 4
=x^2 -4