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a. 2p + 3 + 4p - 1 = 6p + (3-1) = 6p + 2
b. (4p - 3p) + (p + 5q) = (4p - 3p + p) + 5q = 2p + 5q
c. (a + 3a) + (-3b + 2b) + (c -5c) = 4a - b - 4c
pengurangan
kalau pengurangan 'dari' di hitung nya dari belakang
a. 5p - (-9p) = 14p
b. (5p + q) - (3p - 4q) = (-3p + 4q) - (5p + q) = 2p + 3q
c. (4a + 3b - 2c) - (3a - b + c) = a + 4b - 3c
= 2p + 4p + 3 - 1
= 6p + 2
b). (4p - 3p).(p + 5p)
= 4p (p + 5p) - 3p (p+5p)
= 4p² + 20p² - 3p² + 15p²
= 24p² - 18p²
c)....
kurang:
a)....
b)...
c)....