Question

Tentukan hasil pembagian!
a. 8p^2 : (12p^4 : 3p^2)

b. 16x^2y^8:(4x^3 y^2 x2x^2 y^4)

c. (x^3 +5x^2 +2x -8) : (x+2)
d. 3y^3 - 10y^2 +7y +10) : (3y+2)
e. (2y^3 + 6y^2 -11y +4) : (2y-1)

Tolong pakai caranya yaa, makasih...

Answer 1

A. 8p^2 : ( 12p^4 : 3p^2) = 8p^2 : 4 p^2 = 2
b. 16 x^2y^8 : (4x^3Y^2 x 2x^2y^4) = 16 x^2y^8 : 8 x^5y^6 = 2 x^-3y^2
c. ( x^3 + 5x^2 + 2x - 8) : ( x+2) = x^2 + 3x -4 = ( x+4) (x-1)
d. 3y^3 - 10y^2 + 7y + 10 : ( 3y +2) = 3y^2 - 12y + 15
e. (2y^3 + 6y^2 - 11y + 4) : (2y-1)
   hasil bagi y^2 + 7/2 y
   sisa pembagian = -15/2 y + 4