Question

Tentukan gradien yg melalui titik:
A. (-3, -10) & (-1, -5)
B. (-4, 3) & (6, 7)

Answer 1

A. m = (y2-y1)/(x2-x1) = (-5-(-10))/(-1-(-3)) = (-5+10)/(-1+3) = 5/2
persamaan :
y-y1 = m(x-x1)
y-(-10) = 5/2(x-(-3))
y+10 = 5/2(x+3)
______________ x2 (untuk menghilangkan bilangan pecahan agar lebih mudah menghitungnya)
2(y+10) = 5(x+3)
2y+20 = 5x+15
2y = 5x+15-20
2y = 5x-5 atau 2y-5x = -5 atau 2y-5x+5 =0

b. m = (y2-y1)/(x2-x1) = (7-3)/(6-(-4)) = 4/(6+4) = 4/10 = 2/5
persamaan :
y-y1 = m(x-x1)
y-3 = 2/5(x-(-4))
y-3 = 2/5(x+4)
____________ x5
5(y-3) = 2(x+4)
5y-15 = 2x+8
5y = 2x+8+15
5y = 2x+23 atau 5y-2x = 23 atau 5y-2x-23 = 0