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b. (x-1)(x+3)
c. (2x-3)(x+3)
d. (x-1)(x+3)
x²+1x-6x-6 = x (x+1) - 6 (x+1)= (x-6)(x+1)
B 2x diganti 3x-1x
x²-1x+3x-3= x (x-1) + 3 (x-1)= (x+3)(x-1)
C 3x diganti 6x-3x
2x²+6x-3x-9= 2x (x+3) - 3 (x+3)= (2x-3)(x+3)
D sama kayak yg B??
E -5x diganti -8x+3x
2x²-8x+3x-12 = 2x (x-4) + 3 (x-4) = (2x+3)(x-4)