Question

Tentukan energi ikat N-H pada reaksi berikut .
2NH2(g) → N2 + 3H2(I) ∆H = +1173 kj
serius yaa kalo mau bantu , butuh banget soalnya :)

Answer 1

2 NH3 → N≡N + 3 H-H  ΔH = + 1173 kJ

ΔH = ∑I reaktan - ∑I produk
+ 1173 = [2 × (3 N-H)] - [N≡N + 3 H-H]
+ 1173 = [6 × N-H]- [946 + (3 × 463)]
N-H = 584,67 kJ