Question

Tentukan dimensi dari besaran fisika berikut 1.usaha:momentum 2.tekanan kali kecepatan 3.percepatan :daya 4.tekanan kali massa jenis 5.energi pontesial :gaya

Answer 1

Usaha : [ML²T⁻²] : [MLT⁻¹] momentum
tekanan [ML⁻¹T⁻²] X [LT⁻¹] kecepatan
percepatan [LT⁻²] : [ML²T⁻³] daya
energi potensial :

Answer 2

1.Usaha : momentum
= F.s/m.v
= ((kg.m.s^-2 )x m )/ kg.m.s^-1
= s^-2 / s^-1 = s ^-1 = [T]^-1

2. tkanan x kecepatan
= F/A. x s/ t
=(kg.m.s^-2)/ m^2. X. m/s
=kg.s ^-3= [ M ][T]^-3

3.percepatan : daya
=V/t : W/ t= V/W
=(m.s^-1) / kg.m.s^-2 x m
= 1/kg.m.s^-1= 1/ [ M ] [ S ] [ T ]^-1= [T] / [M] [S]

4.tekanan x massa jenis
=F/A X m/ V
=kg.m.s^-2 / m^2 X. kg/ dm^3
=[M]^2.[T]^-2.[L]^-4

5.Ep : F
=m.g.h : m.a
=g.h/a
=m.s^-2.m/ m.s^-2= m=[L]
CMIIW