Tentukan bilangan oksidasi pada atom yang berbeda pada masing-masing berikut : a. Cl₂, P⁴⁻, SO₂, H₂S b. MnO₄²⁻, ZnO₂⁻, HSO₄⁻, NH₄⁺ c.MgCO₃, KClO₄, NaIO₃, Na₃PO₄
siwiata
A. Cl = 0, P = -4, O = -2 S = 4, H = 1 S = 2 b. O = -2 Mn = 6, O = -2 Zn = 3, O = -2 H = 1 S =6, H = 1 N = -3 C. O = -2 Mg = 6, O = -2 K = 1 Cl = 7, O = -2 Na = 1 I= 5, O= -2 Na= 1 P = 5
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Taniathra
A. Cl2 = 0, P4-= -4, SO2: S= -4, O=-2×2=-4, H2S: H=1×2=2, S=-2 b. Mn=6, O=-2×4=-8 Zn= 3, O=-2×2=-4 H=1, S= 6, O=-2×4=-8 N=-3 , H=1×4=4 c. Mg=3, O=-2×3=-6, C=3 K=1, O=-2×4=-8, Cl=7 Na=1, O=-2×3=-6, I=5 Na=1×3=3, O=-2×4=-8, P=5 sorry klo ada yg salah..
b. O = -2 Mn = 6, O = -2 Zn = 3, O = -2 H = 1 S =6, H = 1 N = -3
C. O = -2 Mg = 6, O = -2 K = 1 Cl = 7, O = -2 Na = 1 I= 5, O= -2 Na= 1 P = 5
b. Mn=6, O=-2×4=-8
Zn= 3, O=-2×2=-4
H=1, S= 6, O=-2×4=-8
N=-3 , H=1×4=4
c. Mg=3, O=-2×3=-6, C=3
K=1, O=-2×4=-8, Cl=7
Na=1, O=-2×3=-6, I=5
Na=1×3=3, O=-2×4=-8, P=5
sorry klo ada yg salah..