Question

tentukan bentuk sederhana dari ?​

Answer 1

[tex] {( \frac{3 {a}^{ - 2} b {c}^{ - 3} }{24 {a}^{5} {b}^{ - 3} c} )}^{2} = [/tex]

[tex] {( \frac{ {a}^{ - 2}b {c}^{ - 3} }{8 {a}^{5} {b}^{ - 3} c} ) }^{2} = [/tex]

[tex] \frac{ {( {a}^{ - 2} b {c}^{ - 3} )}^{2} }{ {(8 {a}^{5} {b}^{ - 3}c) }^{2} } = [/tex]

[tex] \frac{ {a}^{ - 2·2} {b}^{2} {c}^{ - 3·2} }{ {8}^{2} {a}^{5·2} {b}^{ - 3·2} {c}^{2} } = [/tex]

[tex] \frac{ {a}^{ - 4} {b}^{2} {c}^{ - 6} }{64 {a}^{10} {b}^{ - 6} {c}^{2} } = [/tex]

[tex] \frac{1}{64} {a}^{ - 4 - 10} {b}^{2 - ( - 6)} {c}^{ - 6 - 2} = [/tex]

[tex] \frac{1}{64} {a}^{ - 4 - 10} {b}^{2 + 6} {c}^{ - 6 - 2} = [/tex]

[tex] \frac{1}{64} {a}^{ - 14} {b}^{8} {c}^{ - 8} = [/tex]

[tex] \frac{ {a}^{ - 14} {b}^{8} {c}^{ - 8} }{64} = [/tex]

[tex] \frac{ {( {a}^{14} {b}^{ - 8} {c}^{8} ) }^{ - 1} }{ {( \frac{1}{64} )}^{ - 1} } = [/tex]

[tex] {( \frac{ {a}^{14} {b}^{ - 8} {c}^{8} }{ \frac{1}{64} } )}^{ - 1} = [/tex]

[tex] \frac{ \frac{1}{64} }{ {a}^{14} {b}^{ - 8} {c}^{8} } = [/tex]

[tex] \frac{1}{64 {a}^{14} {b}^{ - 8} {c}^{8} } = [/tex]

[tex] \frac{1}{64 {a}^{14}· \frac{1}{ {b}^{8} } {c}^{8} } = [/tex]

[tex] \frac{1}{64 {a}^{14} · \frac{ {c}^{8} }{ {b}^{8} } } = [/tex]

[tex] \frac{1}{ \frac{64 {a}^{14} {c}^{8} }{ {b}^{8} } } = [/tex]

[tex] \frac{ {b}^{8} }{64 {a}^{14} {c}^{8} } [/tex]