Question

Tentukan batas batas nilai m agar persamaan kuadrat ( m -x ) x^2 - 4mx + ( m- 2 )=0

Answer 1

Syarat D > 0 dan x1.x2 < 0
(m - 5)x² - 4mx + (m - 2) = 0
a = (m - 5)
b = -4m
c = (m - 2)

D > 0
b² - 4ac > 0
(-4m)² - 4.(m - 5)(m - 2) > 0
16m² - 4(m² - 7m + 10) > 0
16m² - 4m² + 28m - 40 > 0
12m² + 28m - 40 > 0
3m² + 7m - 10 > 0
(3m + 10 )(m - 1) > 0
3m  + 10 > 0 atau m - 1 > 0

m < -10/3 atau m > 1