Question

Tentukan akar persamaan kuadrat x²-3x-4=0

Answer 1

X^ - 3x-4 = 0
(X^-4x)+x-4 = 0
X(x-4) + 1 (x-4) = 0
(X+1)(x-4) = 0

x+1 = 0
X = -1

X-4=0
x=4

Answer 2

X² - 3x - 4 = 0
a : 1
b : -3 ⇒ -4 + 1
c : -4 ⇒ -4 x 1
(x - 4) (x + 1) = 0
- 4 = 0 atau  + 1 = 0
= 4
= -1
Hp = (4,-1)