Tentukan akar persamaan kuadrat dgn cara pemfaktoran
(3x+2)^2 - 5(x+1) - 1= 0
(3x+2)^2 - 5(x+1) - 1= 0
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(3x + 2)(3x + 2) - 5x - 5 - 1 = 0
(3x(3x) + 3x(2) + 2(3x) + 2(2)) - 5x - 4 = 0
(9x² + 6x + 6x + 4) - 5x - 4 = 0
(9x² + 12x + 4) - 5x - 4 = 0
9x² + 12x + 4 - 5x - 4 = 0
9x² + 12x - 5x + 4 - 4 = 0
9x² + 7x = 0
x(9x + 7) = 0
x = 0 atau 9x + 7 = 0
9x = -7
x = -7/9