Tentukan Akar² dari persamaan kuardat berikut ini
a. x²-x-12=0
b. 2x²-x-1=0
a. x²-x-12=0
b. 2x²-x-1=0
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Jawaban:
persamaan kuadrat: ax²+bx+c =0
a). x²-x-12= 0
x²-4x+3x-12=0
x(x-4)+3(x-4)= 0
(x+3)(x-4)= 0 --> solusi: x1 =-3 atau x2= 4
b). 2x²-x-1=0
2x²-2x+x -1 = 0
2x(x - 1)+(x-1) = 0
(2x+1)(x-1) = 0 --> solusi: x1 = -½ atau x2= 1