Question

tentukan akar akar pk dengan memfaktorkan
1. x 2 +6x−27=0
2. x 2 −6x−16=0
3. x 2 +12x+36=0 ​

Bantu jawab buat besok ,mksh​

Answer 1

Penjelasan dengan langkah-langkah:

1.

x² + 6x - 27 = 0

(x - 3)(x + 9) = 0

x1 = 3

x2 = -9

Hp = {3,-9}

2.

x² - 6x - 16 = 0

(x - 8)(x + 2) = 0

x1 = 8

x2 = -2

Hp = {8,-2}

3.

x² + 12x + 36 = 0

(x + 6)(x + 6) = 0

x1 = -6

x2 = -6

Hp = {-6}