Tenemos que:
Sen(2a-c)=Cos(2b+c)
Calcular: F= 2–√Sen(a+b)+Ctg(a+b)
a.
2
b.
5
c.
4
d.
1
e.
3
Sen(2a-c)=Cos(2b+c)
Calcular: F= 2–√Sen(a+b)+Ctg(a+b)
a.
2
b.
5
c.
4
d.
1
e.
3
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