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panjang AD = 6
panjang AO = 2/3 AD = 2/3. 6 = 4
panjang BE = 9
panjang BO = 2/3BE = 6
panjang CO = 2/3 CF
panjang OF = 1/3 CF
cari pajang OF dulu pakai rumus garis berat
OF² = 1/2AO²+1/2OB² - 1/4AB²
OF² = 1/2. 16 + 1/2.36 - 1/4. 64 = 10
OF = √10
panjang OF = 1/3 CF maka CF = 3OF = 3√10
jawaban E