Jawab:
lihat di penjelasan
Penjelasan dengan langkah-langkah:
2.
[tex]y=\frac{2x-3}{4x-5}\\ y(4x-5)=2x-3\\4xy-5y=2x-3\\4xy-2x=5y-3\\x(4y-2)=5y-3\\x=\frac{5y-3}{4y-2} \\f^{-1} (x)=\frac{5x-3}{4x-2}\\ f^{-1} (1)=\frac{5-3}{4-2}\\\\ f^{-1} (1)=\frac{2}{2} \\ f^{-1} (1)=1[/tex]
3.
p q -q p⇒q (p⇒q)∧-q
B B S B S
B S B S S
S B S B S
S S B B B
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Jawab:
lihat di penjelasan
Penjelasan dengan langkah-langkah:
2.
[tex]y=\frac{2x-3}{4x-5}\\ y(4x-5)=2x-3\\4xy-5y=2x-3\\4xy-2x=5y-3\\x(4y-2)=5y-3\\x=\frac{5y-3}{4y-2} \\f^{-1} (x)=\frac{5x-3}{4x-2}\\ f^{-1} (1)=\frac{5-3}{4-2}\\\\ f^{-1} (1)=\frac{2}{2} \\ f^{-1} (1)=1[/tex]
3.
p q -q p⇒q (p⇒q)∧-q
B B S B S
B S B S S
S B S B S
S S B B B