Question

Tema: Ecuación Exponencial

Answer 1

Explicación paso a paso:

[tex] {2}^{x + 1} \times {4}^{x + 2} \times {8}^{x + 3} = 1[/tex]

[tex]{2}^{x + 1} \times {2}^{2(x + 2)} \times {2}^{3(x + 3)} = 1[/tex]

[tex]{2}^{x + 1} \times {2}^{2x + 4} \times {2}^{3x + 9} = 1[/tex]

[tex] {2}^{x + 1 + 2x + 4 + 3x + 9} = 1[/tex]

[tex]{2}^{6x + 14} = (2) {}^{0} [/tex]

[tex]6x + 14 = 0[/tex]

[tex]6x = - 14[/tex]

[tex]x = \frac{ - 14}{6} [/tex]

[tex]x = - \frac{7}{3} [/tex]

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[tex] {4}^{x + 2} = ( {2}^{2} ) {}^{x + 2} = {2}^{2x + 4} [/tex]

[tex] {8}^{x + 3} = ( {2}^{3} ) {}^{x + 3} = {2}^{3x + 9} [/tex]

[tex] {2}^{0} = 1[/tex]