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tegangan(V) = 220v
hambatan (R) = 5 ohm
waktu (t) = 10 menit
=> 10 x 60
=> 600 sekon
ditanya : energi kalor ?
jawab:
energi kalor yg dihasilkan:
= V²/R x t
= 220²/5 x 600
= 48400/5 x 600
= 5.808.000 joule
= 5808 kj
"maaf kalau salah"
W=IxRxIxt
V=IxR
220=Ix5
I=220:5=44A
W=IxRxIxt
=44x5x44x600
=5.808.000J
=5.808KJ