tan( θ + 15°)=cot52, halla θ en grados.... Question from @koomini

April 2023 1 12 Report

tan( θ + 15°)=cot52, halla θ en grados

Mathsolv

Respuesta:

[tex] \theta + 15 + 52 = 90 \\ \theta = 23[/tex]

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